Question

log(1+2+3+)=log1+log2+log3.

Answer 1

we know that  log(m) + log(n) =log(mn) . so that  => log(1)+log(2)+log(3)=log(1x2x3)

                                                                                  =>log(1)+log(2)+log(3)=log(6)

and   log(1+2+3)=log(3+3)=log(6)

    there fore  =>  log(1+2+3)=log1+log2+log3

                       =>  log6=log6

                            hence proved