Question

log(1+2+3)=log1+log2+log3 solve using denominator

Answer 1

we know that  log(m) + log(n) =log(mn) . so that  => log(1)+log(2)+log(3)=log(1x2x3)

                                                                                 =>log(1)+log(2)+log(3)=log(6)

and   log(1+2+3)=log(3+3)=log(6)

   there fore  =>  log(1+2+3)=log1+log2+log3

                      =>  log6=log6

                           hence proved  

Answer 2

L.H.S.= log (1+2+3)
= log 6
=log(1×2×3)
=log 1+ log 2+ log 3
= RHS