Question

log 1/3 (-4.5315) solve it by the help of log and antilog

Answer 1

logx-1/log3  - logx+1/log3 + 2log5-x/log3 <1


-logx-1 - logx+1 + 2log5-x < log3                       (logab = loga + logb)


 2log5-x - logx2-1 < log3


 2log5-x < log3 + logx2-1


 2log5-x < log3(x2-1)


   (5-x)2 < 3(x2-1)