Log (1/81) to the base 9 is equal to
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Answered by
23
log(1/81) to the base 9
log(9^-2) to the base 9
-2 x log9 to the base 9 since log a to the base a is 1
-2x1
-2
log(9^-2) to the base 9
-2 x log9 to the base 9 since log a to the base a is 1
-2x1
-2
Answered by
60
Hi ,
We know that
____________________
1) 1 / a^m = a ^( - m )
2 ) log a ^m = m log a
3 ) log a base a = 1
___________________
1/81 = 1 / 9² = 9^( -2 )
log ( 1 / 81 ) = log [ 9^(-2 ) ]
= ( -2 ) log 9 base 9
= -2
I hope this helps you.
:)
We know that
____________________
1) 1 / a^m = a ^( - m )
2 ) log a ^m = m log a
3 ) log a base a = 1
___________________
1/81 = 1 / 9² = 9^( -2 )
log ( 1 / 81 ) = log [ 9^(-2 ) ]
= ( -2 ) log 9 base 9
= -2
I hope this helps you.
:)
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