log 1 + log 2 + log 3=log x , then x is
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Answer:
x=6
Step-by-step explanation:
Log1 + Log2 + Log3= Log x
or, Log(1 * 2 * 3) = Log x [because log(a) + log(b) = Log (a*b)
also, Log(a) + Log(b) + Log(c) = Log(a*b*c)
or, Log(6)=Log x
or, x=6 [both log got canceled (used antilog on both side)]
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