Question

log(1+x)=2logx find the value of x​

Answer 1

Answer:

log(1+x)=logx^2

remove log on both sides

(1+x)=x^2

x^2-x-1=0

x=1+√1+4/2

x=1+√5/2

x isequalto 1-√5/4

Answer 2

Answer:-

Refer the attachment