Question

log(1+x)-log(1-x)=log(x+3)-log(4-x)

Answer 1

Answer:

-1/5

Explanation:

using the property of log, we can write it as:

log[(1+x)/(1-x)] = log[(x+3)/(4-x)]

removing log on both side and cross multiplying:

(1+x)(4-x) = (x+3)(1-x)

which gives x = -1/5