Question

log 10 (x+1) + log 10 (x-1) = log 10 11 +2 log 10 3​

Answer 1

Answer:

Step-by-step explanation:

Log 10y + log 10x = log10xy

So,log10{(x+1)(x-1)}= log10 11 + log 10 3²

Log10 x²-1= log 11×9

X²-1 = 99

X²= 99 +1

X= under root 100

X = 10

Answer 2

Answer:

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Step-by-step explanation:

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