Log_10(x-3) upon log_10( xsquare - 21) = 1 upon 2
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Solution :
Given : log₁₀(x - 3) / log₁₀(x² - 21) = 1/2
⇒ 2 log₁₀(x - 3) = log₁₀(x² - 21)
⇒ log₁₀(x - 3)² = log₁₀(x² - 21)
⇒ (x - 3)² = x² - 21
⇒ x² - 6x + 9 = x² - 21
⇒ 6x = 9 + 21 = 30
∴ x = 5 , which is the required solution.
Logarithmic rules :
• logₐA + logₐB = logₐ(AB)
• logₐA - logₐB = logₐ(A/B)
• logₐA = logₐB ⇒ A = B
• logₐAᵇ = b logₐA
Swarup1998:
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