Question

Log 1024 base √2 find the value of x

Answer 1

Answer:

log 1024 to the base √2 = 6.0206

Step-by-step explanation:

$log(1024) to \: the \: base \: \sqrt2 = x \\ log(1024) = x {}^{ \sqrt{2} } \\ log(1024) = x {}^{1 \div 2} \\ log(1024) {}^{2} = x ({}^{1 \div 2}) {}^{2} \\ 2 log(1024) = x \\ 2 \times 3.0103 = x \\ x = 6.0206</p><p>$