Question

log 128 to the base root 2​

Answer 1

Answer:

7 is your answer

Step-by-step explanation:

$given \\ log_{2}128 \\ = log_{2} {2}^{7} (by \: prime \: factorisation) \\ = 7 log_{2}2(logn {} ^{x } = xlogn) \\ = 7(1)(here \: in \: logarithms \: log_{2} 2 = 1) \\ = 7$