Question

log 128to the base of root 2​

Answer 1

Answer:

14

Step-by-step explanation:

Let, x = log 128 to the base sqrt 2

($\sqrt{2}$)^x=128

then, (2^1/2)^x=128

(2^x/2)=128

and 128 = 2^7

therefore, (2^x/2) = 2^7

x/2 = 7

x = 2x7

x=14