Math, asked by yadnesh44, 5 months ago

log(15/16)+log(64/81)-log(4/27)-log 5​

Answers

Answered by ojas24082008
1

Answer:

0

Step-by-step explanation:

\begin{gathered} log( \frac{15}{16} ) + log( \frac{64}{81} ) - log( \frac{20}{27} ) \\ log(15) - log(16) + log(64) - log(81) - log(20) + log(27) \\ log(15) - 4 log(2) + 6 log(2) - 4 log(3 ) - log(5) - 2 log(2) + 3 log(3) \\ 0\end{gathered}log(1615)+log(8164)−log(2720)log(15)−log(16)+log(64)−log(81)−log(20)+log(27)log(15)−4log(2)+6log(2)−4log(3)−log(5)−2log(2)+3log(3)0

0 is the answer

Answered by vivekanandrai138
0

Step-by-step explanation:

log 3+log5-4log2+6log2-4log3-2log2+3log3-log5

6log2-6log6

Answer 00000.

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