log {(15+p)(15-p)} = log 81 then find the value of p
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log {(15+p)(15-p)} = log 81
log (15²-p²) = log 81
Remove logarithms on both sides,
15²-p² = 81
225 - p² = 81
p² = 225 - 81
p² = 144
p = ±12
p = 12 , p = -12
log (15²-p²) = log 81
Remove logarithms on both sides,
15²-p² = 81
225 - p² = 81
p² = 225 - 81
p² = 144
p = ±12
p = 12 , p = -12
Answered by
1
log {(15+p)(15-p)} = log 81
log (15²-p²) = log 81
225 - p² = 81
p² = 225-81
p² = 144
p = √144
p = ±12
log (15²-p²) = log 81
225 - p² = 81
p² = 225-81
p² = 144
p = √144
p = ±12
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