log[16/15]+log[15/24]+log[81/48]
Answers
Answered by
2
Here is the solution :
Formulas required :
Log a + log b = log (a*b) ------(1)
Log a - log b = log (a/b) ------(2)
Easiest method :
Using formula (1) we can write the question as,
Log (16/15) + log (15/24) + log (81/48) = log ((16/15)*(15/24)*(81/48))
15 gets cancelled, Now simplifying,
=> log((16*81)/(24*48))
=> log (27/24)
Therefore the answer is log (27/24) or log 27 - log 24,
Long method :
Applying formula (2),
=> Question can re-written as,
log 16 - log 15 + log 15 - log 24 + log 81 - log 48,
=> log 16 + log 81 - log 24 - log 48,
=> log ((16*81)/(24*48))
=> log 27/24 again,
=> log 27 - log 24,
Therefore : The answer is log (27/24) or log 27 - log 24 !
Hope you understand, Have a great day !
Thanking you, Bunti 360 !!
Formulas required :
Log a + log b = log (a*b) ------(1)
Log a - log b = log (a/b) ------(2)
Easiest method :
Using formula (1) we can write the question as,
Log (16/15) + log (15/24) + log (81/48) = log ((16/15)*(15/24)*(81/48))
15 gets cancelled, Now simplifying,
=> log((16*81)/(24*48))
=> log (27/24)
Therefore the answer is log (27/24) or log 27 - log 24,
Long method :
Applying formula (2),
=> Question can re-written as,
log 16 - log 15 + log 15 - log 24 + log 81 - log 48,
=> log 16 + log 81 - log 24 - log 48,
=> log ((16*81)/(24*48))
=> log 27/24 again,
=> log 27 - log 24,
Therefore : The answer is log (27/24) or log 27 - log 24 !
Hope you understand, Have a great day !
Thanking you, Bunti 360 !!
Answered by
1
➡HERE IS YOUR ANSWER⬇
♧ Formula ♧
log (a/b) = log a - log b
log (ab) = log a + log b
log (abc) = log a + log b + log c
log (a^n) = n log a
♧♧ Solution ♧♧
Now,
log (16/15) + log (15/24) + log (81/48)
= log {(16×15×81)/(15×24×48)}
= log (9/8)
⬆HOPE THIS HELPS⬅
♧ Formula ♧
log (a/b) = log a - log b
log (ab) = log a + log b
log (abc) = log a + log b + log c
log (a^n) = n log a
♧♧ Solution ♧♧
Now,
log (16/15) + log (15/24) + log (81/48)
= log {(16×15×81)/(15×24×48)}
= log (9/8)
⬆HOPE THIS HELPS⬅
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