Question

log 16 base 2 - log 2 base 2 find its value?

Answer 1

Answer:

$Value \: of \: log_{2}16-log_{2}2 = 3$

Step-by-step explanation:

$Value \: of \: log_{2}16-log_{2}2$

$=log_{2}2^{4}-log_{2}2$

$=4log_{2}2 - log_{2}2$

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We know the logarithmic laws:

$i) log_{a}n^{m} = mlog_{a}n\\ii) log_{a}a = 1$

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$= 4-1\\=3$

Therefore,

$Value \: of \: log_{2}16-log_{2}2 = 3$

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Answer 2

Answer:

I like the above answer