Math, asked by ankit7237, 1 year ago

log 1728 base root 3law
  log_{ \sqrt{3} }(1728)

Answers

Answered by aman190k
4
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 let :  \: \\  log_{ \sqrt{3} }(1728) = x \\  \\ then :  \\   log_{ \sqrt{3} }(1728) = x \\ \\ 1728 =   { (\sqrt{3} )}^{x}  \\  \\  {4}^{3}  \times  {3}^{3}  =  {3}^{ \frac{x}{2} }  \\  \\  {4}^{3}  =  {3}^{( \frac{x}{2} - 3) }
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ankit7237: after this??
ankit7237: how
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