Question

Log 1728 to the Base 2×3^(1/2)

Answer 1

Answer:

$log_{2 \sqrt{3} }(1728) = 6$

Step-by-step explanation:

$log_{2 \sqrt{3} }(1728)$

$log_{2 \sqrt{3} }( {2 \sqrt{3} }^{6} )$

As per power rule,

$6 log_{2 \sqrt{3} }(2 \sqrt{3} )$

$6(1) = 6$