Question

. Log 2 = 0.301, log 3 = 0.477, log 5 = 0.699 and log 7 = 0.845 Using this information only, find:- a) Log 2.4 b) Log 6/7

Answer 1

Answer:

Log 6/7 = Log6-log7 = (0.477+0.301) - 0.845 = -0.67.

Log2.4 = Log24/10 = Log(2×2×2×3)/10 =3 Log2+Log3 -Log 10 = 0.903-0.477 = 1.380-1 = 0.380.

hope it helps...