Question

Log(2/3) +log(4/5) -log(8/15)

Answer 1

$log( \frac{2}{3} ) + log( \frac{4}{5} ) - log( \frac{8}{15} )$
Using the property,
$log(a) + log(b) = log(ab) \\ log(a) - log(b) = log( \frac{a}{b} )$

$log( \frac{2}{3} \times \frac{4}{5} \times \frac{15}{8} ) \\ = log(1)$

Since log(1) = 0

So, The your answer will be 1.

Answer 2

$\huge{\underline{\underline{\red{Solution→}}}}$

$log( \frac{2}{3} ) + log( \frac{4}{5} ) - log( \frac{8}{15} )$

We know the Property -

• $log(x) + log(y) = log(xy)$

$= log( \frac{2}{3} \times \frac{4}{5} ) - log( \frac{8}{15} ) \\ \\ = log( \frac{8}{15} ) - log( \frac{8}{15} ) \\ \\ = 0$

$\rule{200}{1}$

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