log(2/3)+log(4/5)-log(8/15) find the value
Answers
log(2/3)+log(4/5)-log(8/15)
log(2/3×4/5)-log(8/15)
log(8/15)-log(8/15)
=0
The value of the expression log ( 2 / 3 ) + log ( 4 / 5 ) - log ( 8 / 15 ) is 0.
Given: The expression:
log ( 2 / 3 ) + log ( 4 / 5 ) - log ( 8 / 15 )
To Find: The value of the expression:
log ( 2 / 3 ) + log ( 4 / 5 ) - log ( 8 / 15 )
Solution:
We shall solve this numerical, by making use of the properties of logarithms which state;
log A + log B = log (A×B) ....(1)
log A - log B = log ( A / B ) ....(2)
log 1 = 0 .....(3)
Coming to the numerical, we are given;
The expression:
log ( 2 / 3 ) + log ( 4 / 5 ) - log ( 8 / 15 )
Applying property (1), we can say that;
⇒ log [( 2 / 3 ) × ( 4 / 5 )] - log ( 8 / 15 )
⇒ log ( 8 / 15 ) - log ( 8 / 15 )
Applying property (2), we can say that;
⇒ log [( 8 / 15 ) / ( 8 / 15 )]
⇒ log 1
Now, applying property (3), we get;
⇒ 0
Hence, the value of the expression log ( 2 / 3 ) + log ( 4 / 5 ) - log ( 8 / 15 ) is 0.
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