Question

log 2 (3x-2)=log 1/2 x find the value of x​

Answer 1

Answer:

log

2

(3x−2)=log

2

1

x

Above equation is valid, when x>

3

2

log

2

(3x−2)=log

2

1

x

⇒log

2

(3x−2)=−log

2

x,[∵log

a

1

b=−log

a

b]

⇒log

2

(3x−2)=log

2

x

1

,[∵xloga=loga

x

]

⇒3x−2=

x

1

⇒3x

2

−2x−1=0

⇒x=1, −

3

1

Since, x>

3

2

∴x=1