log√2 64 is equal to
tejasri2:
log √2 base 64. ....? is ur question
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Answered by
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Hi Friend !!!
log √264 = 1.21080
Hope it helps u : )
log √264 = 1.21080
Hope it helps u : )
Answered by
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[0010001111]... Hello User... [1001010101]
Here's your answer...
![log_{ \sqrt{2} }(64) \\ = log_{ {2}^{ \frac{1}{2} } }( {2}^{6} ) \\ log_{ {a}^{x} }(y) = \frac{1}{x} log_{a}(y) \\ log_{a}( {y}^{z} ) = z log_{a}(y) \\ log_{ {a}^{x} }( {y}^{z} ) = \frac{x}{z} log_{a}(y) log_{ \sqrt{2} }(64) \\ = log_{ {2}^{ \frac{1}{2} } }( {2}^{6} ) \\ log_{ {a}^{x} }(y) = \frac{1}{x} log_{a}(y) \\ log_{a}( {y}^{z} ) = z log_{a}(y) \\ log_{ {a}^{x} }( {y}^{z} ) = \frac{x}{z} log_{a}(y)](https://tex.z-dn.net/?f=+log_%7B+%5Csqrt%7B2%7D+%7D%2864%29++%5C%5C++%3D++log_%7B+%7B2%7D%5E%7B+%5Cfrac%7B1%7D%7B2%7D+%7D+%7D%28+%7B2%7D%5E%7B6%7D+%29++%5C%5C++log_%7B+%7Ba%7D%5E%7Bx%7D+%7D%28y%29++%3D+++%5Cfrac%7B1%7D%7Bx%7D+log_%7Ba%7D%28y%29++%5C%5C++log_%7Ba%7D%28+%7By%7D%5E%7Bz%7D+%29++%3D+z+log_%7Ba%7D%28y%29++%5C%5C++log_%7B+%7Ba%7D%5E%7Bx%7D+%7D%28+%7By%7D%5E%7Bz%7D+%29++%3D++%5Cfrac%7Bx%7D%7Bz%7D++log_%7Ba%7D%28y%29+)
By using this property in the above equation...
![log_{ {2}^{ \frac{1}{2} } }( {2}^{6} ) \\ = \frac{6}{ \frac{1}{2} } log_{2}(2) \\ = 12 log_{2}(2) \\ = 12 log_{ {2}^{ \frac{1}{2} } }( {2}^{6} ) \\ = \frac{6}{ \frac{1}{2} } log_{2}(2) \\ = 12 log_{2}(2) \\ = 12](https://tex.z-dn.net/?f=+log_%7B+%7B2%7D%5E%7B+%5Cfrac%7B1%7D%7B2%7D+%7D+%7D%28+%7B2%7D%5E%7B6%7D+%29+%5C%5C++%3D++%5Cfrac%7B6%7D%7B+%5Cfrac%7B1%7D%7B2%7D+%7D+++log_%7B2%7D%282%29++%5C%5C++%3D+12+log_%7B2%7D%282%29++%5C%5C++%3D+12)
[0110100101]... More questions detected... [010110011110]
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Here's your answer...
By using this property in the above equation...
[0110100101]... More questions detected... [010110011110]
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