log 2 by 3 + log 3 by 4 + log 1 by 5 command kya hai
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Answered by
1
Hi ,
log ( 2/3 ) + log ( 3/4 ) + log ( 1/5 )
[ log x + log y + log z = log xyz ]
= log [ 2/3 × 3/4 × 1/5 ]
= log ( 1/10 )
= log ( 10 ) ^ -1
= -1
[ since 1 ) log m^n = n log m
2 ) log 10 base ( 10 ) = 1 ]
I hope this helps you.
: )
log ( 2/3 ) + log ( 3/4 ) + log ( 1/5 )
[ log x + log y + log z = log xyz ]
= log [ 2/3 × 3/4 × 1/5 ]
= log ( 1/10 )
= log ( 10 ) ^ -1
= -1
[ since 1 ) log m^n = n log m
2 ) log 10 base ( 10 ) = 1 ]
I hope this helps you.
: )
vishnu176:
thanks
Answered by
0
Hi,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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