Question

log 2+log(x+3)- log(3x-5)= log 3​

Answer 1

Answer:

log 2-log (3x-5)=log 3 -log (x+3)

log (2/3x-5)=log (3/x+3)

2/3x-5=3/x+3

$\frac{2}{3x - 5} = \frac{3}{x + 3 } \\ 9x - 15 = 2x + 6 \\ 9x - 2x = 6 + 15 \\ 7x = 21 \\ x = 3$