Question

log, (2 + x) < 1
please solve this inequality​

Answer 1

2+x > 0 => x>–2 ------(1)

${x}^{2} > 0$

$= > \: \: \: x > 0 \: \: \: \: \: - - - -(2)$

x^2 ≠ 1 => x≠{–1,1} ----- (3)

(1) n (2) n (3)

x € (0,∞)–{1} ----(4)

$log_{ {x}^{2} }(2 + x) < 1$

$x + 2 < {1}^{ {x}^{2} }$

$x + 2 < 1$

$x < - 1 \: \: \: \: \: \: - - - - (5)$

(4) n (5)

x € ¢ (fi)