Question

log 2020 base 2020 +log 1 base 2020​

Answer 1

Answer:

$log_{2020}(2020) + log_{2020}(1) = 1 + 0 = 1$

Answer 2

log 2020 base 2020 +log 1 base 2020​ is 1

Step-by-step explanation:

We have to findthe value of $log_{2020}(2020)+log_{2020}(1)$

We know $log_{m}m=1$   , where m is the base

            and $log_{m}1=0$

so $log_{2020}(2020)+log_{2020}(1)$

       $=1+0$

      $=1$

so $log_{2020}(2020)+log_{2020}(1)=1$