Question

log⁡(216/125) =
3 X log5/log6
3(log6 X log5)
3(log6+log5)
3(log6-log5)
Find the single logarithm ​

Answer 1

Answer:

Prove that `(log 3 sqrt3+log sqrt8 -log sqrt125)/(log 6 -log5)` = `3/2`. More Related Question & Answers ... Value of x satifying (log)_(10)sqrt(1+x.

Step-by-step explanation:

Answer 2

Answer:

2log3+3log5+5log2

We know that, logxy

=ylogx,

Using the above property we can reduce the given equation as,

=log3²+log5³+log²

=log9+log125+log32

also, logx+logy+logz=logxyz, hence we can write the above as,

=log(9×125×32)

=log(36000)

∴ 2log3+3log5+5log2 can be written as a single logarithm as log36000.

Step-by-step explanation:

hope it's help you!!!