log(225/32)–log(25/81)+log(64/729)
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Given log(225/32) - log(25/81) + log(64/729).
We know that log a - log b = log (a/b)
log(225/32) = log (225/32/25/81) + log(64/729)
= log (729/32) + log(64/729)
We know that log a + log b = log ab.
= log(729/32 * log 64/729)
= log 2.
Hope this helps!
The value is 10 base log 2.
We know that log a - log b = log (a/b)
log(225/32) = log (225/32/25/81) + log(64/729)
= log (729/32) + log(64/729)
We know that log a + log b = log ab.
= log(729/32 * log 64/729)
= log 2.
Hope this helps!
The value is 10 base log 2.
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