Question

log 25 log 49÷ log 5 log 7
​

Answer 1

To solve this question, we must know that

$\big\black\boxed{logx^a = alogx}$

log25 = log5² = 2log5

log49 = log7² = 2log7

So

log25log7 ÷ log5log7

= (2log5×2log7)÷(log5log7)

= 2×2

= 4