Math, asked by avinashkumarchunnu8, 10 months ago

log 26/51 - log 91/119​

Answers

Answered by Anonymous
13

Answer: log2 - log3

Step-by-step explanation:

Rule: logA -logB = log(A÷B)

log 26/51 - log 91/119​

= log (26/51)÷ (91/119)

=log[\frac{26}{51} *\frac{119}{91}]\\\\=log[\frac{13*2}{17*3} *\frac{17*7}{13*7} ]\\\\=log[\frac{2}{3} ]\\\\=log2 - log3

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