Math, asked by annamsnrao, 7 months ago

log√2base a =1/6 then a=?

Answers

Answered by Anonymous
9

Answer:

logbase(a) root of(2) = 1/6

convert to:-

a^1/6 = squareroot 2

a = (sqrt2)^6

a = 8

Answered by rishkrith123
4

Answer:

The value of a is 8.

Step-by-step explanation:

Given,

\log _{a}^{\sqrt{2}}= \frac{1}{6}

To find,

The value of 'a'

concept,

Some properties of the logarithmic function:

  • If b = logₐⁿ then n = aᵇ...(1)
  • ln(aˣ) = x ln (a)......(2)
  • ln(ab)= ln(a)+ln(b)....(3)

Calculation,

\log _{a}^{\sqrt{2}}= \frac{1}{6}...(4)

Considering the L.H.S

i.e. \log _{a}^{\sqrt{2}}

using the property number (2) we can get,

\log _{a}^{\sqrt{2}} = \frac{1}{2} \log_{a}^{2}...(5)

Equating equations (5) and (4) we get:

1/2 logₐ² = 1/6

⇒ logₐ² = 1/3

Apllying the property (1) we get:

⇒ 2 = a^{1/3}

⇒ 8 = a

Therefore, the value of a is 8.

#SPJ2

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