Question

Log 2to the base 10 =0.3010 then log 32 to the base 10 equal to

Answer 1

Answer:

1.050

Step-by-step explanation:

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Answer 2

$\displaystyle \sf log_{10}(32) = \bf {1.505} \: \: \sf{ when \: log_{10}(2) = 0.3010}$

Given :

$\displaystyle \sf log_{10}(2) = 0.3010$

To find :

$\displaystyle \sf log_{10}(32)$

Formula Used :

We are aware of the formula on logarithm that

$\sf{\: log( {a}^{n} ) = n log(a) }$

Solution :

Step 1 of 2 :

Write down the given value

Here it is given that

$\displaystyle \sf log_{10}(2) = 0.3010$

Step 2 of 2 :

Find the required value

$\displaystyle \sf log_{10}(32)$

$\displaystyle \sf = log_{10}( {2}^{5} )$

$\displaystyle \sf = 5 \times log_{10}(2)\: \: \: \bigg[ \: \because \:log( {a}^{n} ) = n \times log(a )\bigg]$

$\displaystyle \sf = 5 \times 0.3010$

$\displaystyle \sf = 1.505$

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