Question

log 2x+1 base 4=log x+2 base 4 -log 3 base 4 then find x​

Answer 1

Answer:

logx2.log2x2.log24x>1

log2x1.log22x1.(log24+log2x)>1

log2x.(log22+log2x)1.(log222+log2x)>1

If x=0,log2x=−1 and if x>0,x=21

2+log2x>log2x(log22+log2x) 

2+log2x>log2x(1+log2