Question

log( 2x+3) – log( -5x+2) = log 7

Answer 1

Step-by-step explanation:

=> log [ 2x+3/2-5x] = log 7

[ log m - log n = log [m/n] ]

now taking antilog on both sides, we get

=> 2x+3/2-5x = 7/1

=> 7(2-5x) = 2x+3

=> 14 - 35x = 2x + 3

=> 14-3 = 2x + 35x

=> 11 = 37x

=> x = 11/37