Math, asked by soumyabasuri419, 1 year ago

Log 3^2 ,log6^2 , log 12 ^2 are in


gluco: what is to be done with the question?pls tell.

Answers

Answered by VEDULAKRISHNACHAITAN
2

Answer:

Arithmetic Progression(A.P)

Step-by-step explanation:

We say a, b and c are in Arithmetic Progresson(A.P),

if b-a = c-b

We will be using some properties of logarithms here,

log aⁿ  = n log a-------(*) and

log b - log a = log (b/a)-------(**).

Consider log6² - log3² = log(6²/3²)=

log2²(using log b - log a = log (b/a)))

= 2 log 2, (using log aⁿ  = n log a),

  and  log12² -  log6² = log(12²/6²)

=log2²,  using log b - log a = log (b/a).

=2log2  using log aⁿ  = n log a.

Since ,both have the same common difference, we say that  the given numbers are in A.P


Answered by MaheswariS
1

Answer:


Step-by-step explanation:

log(3²), log(6²), log(12²) are in A.P

Concept:

1. Quotient rule:

log(M/N) = logM - logM


2. If b - a = c - b then a, b, c are in AP




log(3²)= log 9



log(6²)= log 36



log(12²)= log 144



log 36 - log 9 = log(36/9) = log 4


log 144 - log 36 = log(144/36) = log 4


log 36 - log 9 =log 144 - log 36

⇒ log9, log36, log144 are in A.P


Hence log(3²), log(6²), log(12²) are in A.P

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