Log(3) 9+log(5) 625+log(7)343 is
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heres ur ans
just substitute values and add
and thts enough
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The answer is 9
Given problem: ㏒₃ 9 + ㏒₅ 625 + ㏒₇ 343
To find: The value of ㏒₃ 9 + ㏒₅ 625 + ㏒₇ 343
Solution:
㏒₃ 9 + ㏒₅ 625 + ㏒₇ 343
⇒ ㏒₃ 3² + ㏒₅ (5)⁴ + ㏒₇ 7³
⇒ 2 ㏒₃ 3 + 4 ㏒₅ 5 + 3 ㏒₇ 7 [ ∵ ㏒ a ᵇ = b ㏒ a ]
= 2 (1) + 4 (1) + 3 (1) [ ∵ ㏒ₐ a = 1 ]
= 2 + 4 + 3 = 9
Therefore, ㏒₃ 9 + ㏒₅ 625 + ㏒₇ 343 = 9
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