log 3 to the base 10 =0.4771then number of digits in(81)power 11 is is
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Answer:
The number of zeroes will be
=∣log
10
(3
−100
)∣
=∣−100(log
10
(3))∣
=∣−47.71∣
=47.71
Taking the integral part (since number of zeroes has to be an integer, there will be 47 zeros.
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