Log 3 (x +3) + log3 (x + 5) = 1.
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log 3(x+3)+log3(x+5)=1
log a+logb=log ab
log(3(x+3)×3(x+5))
log(3x+9×3x+15)
log(9x^2+72x+135)=log10base 10
3x+9×3x+15=1
x=3,5
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