Math, asked by babul65, 11 months ago

log_{3}x+log_{9}x^2+log_{27}x^3=9

Answers

Answered by hananb
1

Answer:

The given equation is equal to :

(log3)x + (2.log3)x^2 + (3.log3)x^3 = 9

So x + 2.x^2 + 3.x^3 = 9/log3

Now solve.

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