Question

log (32/27) + log (81/49) - 2 log (4/7)

Answer 1

Hi ,

we know that ,

1 ) log m + log n = log mn

2 ) log m - log n = log ( m / n )

3 ) n log m = log m^n

Now according to the problem given,

log ( 32 / 27 )+log (81 /49) - 2 log ( 4 / 7 )

= log [ ( 32/27 )(81/49 ) ] - log ( 4/7)²

= log ( 32 × 3 )/49 - log ( 16 / 49)

= log [ ( 96/49 ) / ( 16 / 49 )]

= log [ ( 96 × 49 ) / (49 × 16 ) ]

after cancellation ,

= log 6

I hope this helps you.

:)