Question

log (3x+2)+log(3x-2)=5log2

Answer 1

log (3x + 2) + log (3x - 2) = 5log2

we can write

log [(3x + 2)(3x - 2)] = 5log2

(3x + 2)(3x- 2) = 32

$9x {}^{2} - 4 = 32$

$9x {}^{2} = 36$

$x {}^{2} = 36 \div 9$

x = 2

Thanks

Answer 2

log ( 3x + 2 ) + log ( 3x - 2 ) = 5 log2

log ( 3x)² - (2² ) = log2^5

Cancelling log on both sides,

9x² - 4 = 32

9x² = 36

x² = 36/9

x² = (6/3)²

x = 6/3 = 2 .

Hope helped! ^^