log(3X+2)+log(3X-2)=5log2
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Answer:
Step-by-step explanation:
log (3x + 2) + log (3x - 2) = 5log2
we can write
log [(3x + 2)(3x - 2)] = 5log2
(3x + 2)(3x- 2) = 32
9x {}^{2} - 4 = 32
9x {}^{2} = 36
x {}^{2} = 36 \div 9
x = 2
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