Log 3x + log 9x = 12
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Answered by
0
We see that we have different bases. Thus, we have to make both logs the same base. Let's change log9 x to base 3.
Answered by
1
Answer:
Step-by-step explanation:
→㏒27X^2=12
→27X^2=10^12
→X=10^6/33
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