Question

log 4 +1/3 log 125 -1/5 log 32

Answer 1

♧♧HERE IS YOUR ANSWER♧♧

Given :

$log4 + \frac{1}{3} log125 - \frac{1}{5} log32 \\ \\ = log4 + log { ({5}^{3} )}^{ (\frac{1}{3}) } - log { ({2}^{5} )}^{( \frac{1}{5}) } \\ \\ = log4 + log5 - log2 \\ \\ = log(4 \times 5) - log2 \\ \\ = log20 - log2 \\ \\ = log \frac{20}{2} \\ \\ = log10 \\ \\ = 1$

♧♧HOPE THIS HELPS YOU♧♧