Question

log 4 base2 +log 3 base 2​

Answer 1

$\bf \large Hola!$

• To FinD :

$\mapsto \sf \: log_{2}(4) + log_{2}(3) = {?}$

• RequireD ConcepT :

$\sf \mapsto \: log_{a}(mn) = log_{a}(m) + log_{a}(n)$

• SolutioN :

$\sf log_{2}4 + log_{2}3$

$\implies \sf log_{2}(4 \times 3)$

$\implies \sf log_{2}(12)$

• ConcepT BoosteR :

$\sf1) log_{a}(1) = 0$

$\sf 2) log_{a}(a) = 1$

$\sf3) log_{a}( {b}^{n} ) = n \: log_{a}(b)$

$\sf 4) log_{a}( \frac{b}{ c} ) = log_{a}(b) - log_{a}(c)$

$\sf5) log_{a}(b) \times log_{b}(d) = log_{a}(d)$

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