Question

Log 4 to the base 3 multiple log 81 to the base 4

Answer 1

Answer:

$log_{3}(4) \times log_{4}(81) \\ = \frac{ log(4) }{ log(3) } \times \frac{ log(81) }{ log(4) } \\ = \frac{ log( {3}^{4} ) }{ log(3) } \\ = \frac{4 log(3) }{ log(3) } \\ = 4$