Question

log(4x-3)=log(2x+1)-log3

Answer 1

Log(4x-3)=log(2x+1 /3)
4x-3 = 2x+1 / 3
cross multiply then
12x-9=2x+1
10x = 10
x=1
i hope this help u

Answer 2

log(4x-3)=log(2x+1)/3
4x-3=(2x+1)/3
12x-9=2x+1
10x=10
x=1.1