Question

log ( 4x-3)= log (x+1)+ log 3

Answer 1

Step-by-step explanation:

✏Given here

↪log(4x-3)=log(x+1)+log3

↪log(4x-3)=log3(x+1)

[ we know , log x = log y=> x = y ]

↪(4x-3)=3(x+1)

↪4x-3x = 3+3

↪x = 6.

⏩Hopes its helps u.

Answer 2

Answer:

Log ( 4x-3)= log (x+1)+ log 3

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.

So

4x - 3 = (x+1) 3

4x - 3 = 3x + 3

4x - 3x = 3 + 3

x =6

Thus for the value of x =6 the equation

Thus for the value of x =6 the equationLog ( 4x-3)= log (x+1)+ log 3

Thus for the value of x =6 the equationLog ( 4x-3)= log (x+1)+ log 3Holds good