Question

Log 5 + log ( 5x+3)= 1+log (x+3) solve x

Answer 1

Answer:

$\large\bold\red{x=1}$

Step-by-step explanation:

Given,

$log(5) + log(5x + 3) = 1 + log(x + 3)$

Now ,

We know that,

• $log(a) + log(b) = log(ab)$
• $1 = log(10)$

Therefore,

We get,

$= > log(5) + log(5x + 3) = log(10) + log(x + 3) \\ \\ = > log(5(5x + 3)) = log(10(x + 3)) \\ \\ = > 5(5x + 3) = 10(x + 3) \\ \\ = > 5x + 3 = 2(x + 3) \\ \\ = > 5x + 3 = 2x + 6 \\ \\ = > 5x - 2x = 6 - 3 \\ \\ = > 3x = 3 \\ \\ = > x = \frac{3}{3} \\ \\ = > \large \boxed{ \bold{x = 1}}$

Answer 2

To find :---

• Log 5 + log ( 5x+3)= 1+log (x+3) solve for x ..

Formula used :----

• Log a + log b = log(a+b)
• log10 = 1

Solution :----

putting 1 = log 10 in RHS we get,

→ Log 5 + log ( 5x+3)= log10 + log (x+3)

now, using Log a + log b = log(a+b) we get,

→ log(5(5x+3)) = log(10(x+3))

→ 5(5x+3) = 10(x+3)

→ 25x + 15 = 10x + 30

→ 25x - 10x = 30 - 15

→ 15x = 15

→ x = 15/15 = 1 .

Hence , value of x is 1 ....